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What is the probability the number contains at least one digit 2?
The probability is 1. And the same is true for any other digit.This counter-intuitive result can be proved as follows:Ignore numbers with leading zeros.There are 9 1-digit numbers of which 8 do not contain any 2s;There are 90 2-digit numbers of which 8*9 do not contain any 2s;There are 900 3-digit numbers of which 8*9*9 do not contain any 2s;and so on.The total number of k digit numbers is 9 + 90 + 900 + ... + 9*10^(k-1)= 9*[10^k-1]/[10 - 1] = 10^k - 1Of these, the count of numbers which do not contain any 2s = 8 + 8*9 + 8*9^2 + ... + 8*9^(k-1)= 8*[9^k-1]/[9 - 1] = 9^k - 1So the probability that the numbers do not contain any 2s is [9^k - 1]/[10^k - 1] which, as k gets larger, approaches 9^k/10^k = (0.9)^k which tends to 0.So, the probability that the number DOES contain at least one 2 = 1 - Pr(It contains none) = 1 - 0 = 1.
What is the sum of k squared and k?
k^2 + k = k^2 + k k^2 x k = k^3
What does 2 less than k is?
The formula is 2-k. The answer depends on the value of k.
How do you find the two square roots of i imaginary number Answer in rectangular form?
The two square roots of i are (k, k) and (-k, -k) where k = sqrt(2)/2 = 1/sqrt(2).
What is the value of k when the line y equals 3x plus 1 is a tangent to the curve of y2 plus x2 equals k?
If: y = 3x +1 then y^2 = 9x^2 +6x +1 If: y^2 +x^2 = k then y^2 = k -x^2 So: 9x^2 +6x +1 = k -x^2 Transposing terms: 10x^2 +6x +(1 -k) = 0 Using the discriminant: 6^2 -4*10*(1 -k) = 0 Solving the discriminant: k = 1/10
Does cocodamol contain opiates?
yes co-dydramol does contain opiates, opiates are the oily substance which is with retracted from the poppy seed. Also an opiate is a pain killer.
Does amoxicillin contain opiates?
no
Do blood pressure medications contain opiates?
No. Opiates are not for the use of lowering blood pressure, unless your doctor is confused.
Dilaudid and percocet how they show in urine?
They are all opiates meaning they test your urine for opium which all opiates contain.
Is there OPIATES in pot?
does hydrocodone show positive on a pot drug test Only if your pot was laced with opiates. If not, no. Marijuana does not naturally contain opiates.
Does Vyvanse contain opiates?
No; Vyvanse contains the prodrug lisdexamfetamine which is dextroamphetamine. Dextroamphetamine is classified as a stimulant and is not chemically related in action or structure to opiates.
Do inhalers contain opiates?
No, inhalers do not contain opiates. Inhalers are primarily used to deliver medications such as bronchodilators or corticosteroids, which help manage respiratory conditions like asthma or chronic obstructive pulmonary disease (COPD). Opiates are a class of drugs used primarily for pain relief and are not typically found in inhalation therapies.
What foods contain Vitamin K?
Dark green vegetables such as spinich contain vitamin K
What are opanas made of?
Opanas contain oxymorphone, which is among one of the most powerful opiates there are on the market.
Do lidoderm patches contain opiates?
No. Lidoderm patches contain a non-narcotic called lidocaine. Lidocaine is in the novacaine family and is simply a numbing agent.
Does sugar free gelatin contain vitamin K?
Gelatin does not contain Vit. K, with or without sugar.
What is the probability the number contains at least one digit 2?
The probability is 1. And the same is true for any other digit.This counter-intuitive result can be proved as follows:Ignore numbers with leading zeros.There are 9 1-digit numbers of which 8 do not contain any 2s;There are 90 2-digit numbers of which 8*9 do not contain any 2s;There are 900 3-digit numbers of which 8*9*9 do not contain any 2s;and so on.The total number of k digit numbers is 9 + 90 + 900 + ... + 9*10^(k-1)= 9*[10^k-1]/[10 - 1] = 10^k - 1Of these, the count of numbers which do not contain any 2s = 8 + 8*9 + 8*9^2 + ... + 8*9^(k-1)= 8*[9^k-1]/[9 - 1] = 9^k - 1So the probability that the numbers do not contain any 2s is [9^k - 1]/[10^k - 1] which, as k gets larger, approaches 9^k/10^k = (0.9)^k which tends to 0.So, the probability that the number DOES contain at least one 2 = 1 - Pr(It contains none) = 1 - 0 = 1.
