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What is the formula for a 15-75-90 triangle?
1, 2+sqrt3, sqrt2+sqrt6
Which expression is a fourth root of negative 1 plus sqrt3?
[-1+sqrt(3)]1/4
How do you evaluate the following expression arccot of the negative square root of three without using a calculator?
since x is negative you use the identity cot-1(x)=tan-1(1/x)+pi. Tan-1(1/-sqrt3) + pi 5pi/6 + pi =pi
Is 3 over 12 and 1 over 12 equal?
3 over 12 and 1 over 12 are not equal.
Is 1 over 6 equal to 1 over 3?
1/6 is equal to 2*1/2*31/6 is not equal to 2/6----------------------------------
How can I solve tan of 3 theta -sqrt of 3 equals 0 for theta?
tan3A-sqrt3=0 tan3A=sqrt3 3A=tan^-1(sqrt3) 3A= pi/3+npi A=pi/9+npi/3 n=any integer
What is the area of a square with the dimension of 1 plus sqrt3?
4 + 2sqrt3
What is the formula for a 15-75-90 triangle?
1, 2+sqrt3, sqrt2+sqrt6
Which expression is a fourth root of negative 1 plus sqrt3?
[-1+sqrt(3)]1/4
What is the square root of 3 times the negative square root of 3?
sqrt 3/sqrt3 = 1
How does one find formula for an equilateral triangle from the generic formula x bh over 2 x?
the formula for the area of equilateral triangle with side length a is (a^2)(sqrt(3)/4 ) So draw an equilateral triangle with sides a,a,a. Now divide it into two triangles by bisecting the top angle and extending that line down so it makes a 90 angle with the base. (any angle will do since it is symmetric, but I am trying to help you draw it) Now the new half triangle you have is a 30 60 90 triangle since the top angle is half the original which was 60 and the lower left angle is still 60. The 90 degree angle is the third angle and we are drawing it this way so we have a that the side between the 30 and 90 degree angles is the height of the triangle and we can use 1/bh which is the area formula. The new base has length a and the height is sqrt3(a) because it is a 30-60-90 triangle so 1/2 bxh= 1/2(1/2 )a (sqrt3)a=(1/4)a^2( sqrt3 )since 1/2 base = a/4 and height is sqrt3 x a
How does one get the formula for an equilateral triangle?
the formula for the area of equilateral triangle with side length a is (a^2)(sqrt(3)/4 ) So draw an equilateral triangle with sides a,a,a. Now divide it into two triangles by bisecting the top angle and extending that line down so it makes a 90 angle with the base. (any angle will do since it is symmetric, but I am trying to help you draw it) Now the new half triangle you have is a 30 60 90 triangle since the top angle is half the original which was 60 and the lower left angle is still 60. The 90 degree angle is the third angle and we are drawing it this way so we have a that the side between the 30 and 90 degree angles is the height of the triangle and we can use 1/bh which is the area formula. The new base has length a and the height is sqrt3(a) because it is a 30-60-90 triangle so 1/2 bxh= 1/2(1/2 )a (sqrt3)a=(1/4)a^2( sqrt3 )since 1/2 base = a/4 and height is sqrt3 x a
How do you evaluate the following expression arccot of the negative square root of three without using a calculator?
since x is negative you use the identity cot-1(x)=tan-1(1/x)+pi. Tan-1(1/-sqrt3) + pi 5pi/6 + pi =pi
How do you calculate the height of an equilateral triangle given the lengths of all 3 sides?
Half the length of one side multiplied by (square root of 3)/(2). in triangle ABC with height H: (A•sqrt3)/2 or A (sqrt3)/2 This is because of the Pythagorean theorem. You draw a line from the top vertex of the triangle vertically to the bottom side. This line is perpendicular to the bottom side and it will bisect that side. Now you want to know the length of your new line. On each side of it, you have a smaller triangle, one side with the length of the side of the original triangle (let's call it s) and one side with length half that, (1/2)s. Since the side with length s will be the hypotenuse of the triangle, we know s2 = (s/2)2 + h2 by the Pythagorean theorem. (h stands for height.) s2 = s2/4 + h2 s2 (1-1/4) =h2 s2(3/4) =h2 (sqrt3)s/2 = h
What is the factor of x2-3?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 253) divided by 2 x = 8.452986860293432 x = -7.452986860293433
Is 3 over 12 and 1 over 12 equal?
3 over 12 and 1 over 12 are not equal.
Is 1 over 6 equal to 1 over 3?
1/6 is equal to 2*1/2*31/6 is not equal to 2/6----------------------------------
