Yes.
sqrt(3)/3 = sqrt(3)/[sqrt(3)*sqrt(3)] = 1/sqrt(3)
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1, 2+sqrt3, sqrt2+sqrt6
[-1+sqrt(3)]1/4
since x is negative you use the identity cot-1(x)=tan-1(1/x)+pi. Tan-1(1/-sqrt3) + pi 5pi/6 + pi =pi
3 over 12 and 1 over 12 are not equal.
1/6 is equal to 2*1/2*31/6 is not equal to 2/6----------------------------------