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the formula for the area of equilateral triangle with side length a is (a^2)(sqrt(3)/4 ) So draw an equilateral triangle with sides a,a,a. Now divide it into two triangles by bisecting the top angle and extending that line down so it makes a 90 angle with the base. (any angle will do since it is symmetric, but I am trying to help you draw it) Now the new half triangle you have is a 30 60 90 triangle since the top angle is half the original which was 60 and the lower left angle is still 60. The 90 degree angle is the third angle and we are drawing it this way so we have a that the side between the 30 and 90 degree angles is the height of the triangle and we can use 1/bh which is the area formula. The new base has length a and the height is sqrt3(a) because it is a 30-60-90 triangle so 1/2 bxh= 1/2(1/2 )a (sqrt3)a=(1/4)a^2( sqrt3 )since 1/2 base = a/4 and height is sqrt3 x a

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Q: How does one find formula for an equilateral triangle from the generic formula x bh over 2 x?
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