a2 - 4a + 4
l a2 b2 is c2!!Its completely norma
Pythagoras' theorem. This is telling us that, for a right angled triangle, the square of the hypotenuse (c2) is equal to the sum of the square of the other two sides (a2 + b2).
A2 + B2 = C2 If C=8, then A2 + B2 = 64
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
a2+2a2b+2ab2+b2
(a+b)(a+b)Also equal to a2+2ab+b2
a2
(A+B)2 = (A+B).(A+B) =A2+AB+BA+B2 =A2+2AB+ B2 So the Answer is A + B the whole square is equal to A square plus 2AB plus B square. Avinash.
a2 - 4a + 4
l a2 b2 is c2!!Its completely norma
Pythagoras' theorem. This is telling us that, for a right angled triangle, the square of the hypotenuse (c2) is equal to the sum of the square of the other two sides (a2 + b2).
sqrt(a2 + b2) can't be simplified. Neither can (a2 + b2) .
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
A2 + B2 = C2 If C=8, then A2 + B2 = 64
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)