Yes.
If two chords intersect within a circle, the product of the two segments of one chord equals the product of the two segments of the other chord. In short, if two chords intersect in a circle, their length is equal.
A straight line that intersects a circle's circumference at two points will create a chord of which the circle's diameter is its largest chord.
Yes, and the two points are located on the circumference of the circle
A chord is when two points in a circle are connected by segment. A diameter is a chord, but not a radius. The radius is not a complete segment in the circle
Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.
A chord line intersects a circle at two points of which the circle's diameter is its largest chord.
well its true that every chord contains two points of the circumference of a circle 'cos a chord is the straight line between two points on the circumference
If two chords intersect within a circle, the product of the two segments of one chord equals the product of the two segments of the other chord. In short, if two chords intersect in a circle, their length is equal.
A straight line that intersects a circle's circumference at two points will create a chord of which the circle's diameter is its largest chord.
Yes, and the two points are located on the circumference of the circle
It is a chord of which the circle's diameter is its largest chord
A line segment joining two points on the circumference of a circle and the diameter is the largest chord in a circle.
A chord is when two points in a circle are connected by segment. A diameter is a chord, but not a radius. The radius is not a complete segment in the circle
A chord
chord
A chord
Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.