The larger your sample size, the less variance there will be. For instance, your information is going to be much more substantial if you took 1000 samples over 10 samples.
Yes, Mean is given by, E(X) sum of samples / no. of samples. Variance is Var.(X) = E(X^2) - [E(X)]^2. It is the 1st term which makes the variation of variance independent of mean. In other words, Variance gives a measure of how far the samples are spread out.
The two distributions are symmetrical about the same point (the mean). The distribution where the sd is larger will be more flattened - with a lower peak and more spread out.
because of two things- a) both positive and negative deviations mean something about the general variability of the data to the analyst, if you added them they'd cancel out, but squaring them results in positive numbers that add up. b) a few larger deviations are much more significant than the many little ones, and squaring them gives them more weight. Sigma, the square root of the variance, is a good pointer to how far away from the mean you are likely to be if you choose a datum at random. the probability of being such a number of sigmas away is easily looked up.
That only happens when you sample a population that is normally distributed. In that case, the question and its answer are quite circular.
The larger your sample size, the less variance there will be. For instance, your information is going to be much more substantial if you took 1000 samples over 10 samples.
The variance decreases with a larger sample so that the sample mean is likely to be closer to the population mean.
No. The standard deviation is the square root of the variance.
When we discuss a sample drawn from a population, the larger the sample, or the large the number of repetitions of the event, the more certain we are of the mean value. So, when the normal distribution is considered the sampling distribution of the mean, then more repetitions lead to smaller values of the variance of the distribution.
yes, it can be smaller, equal or larger to the true value of the population varience.
The probability distribution is P(X = 1) = 1/36 P(X = 2) = 3/36 P(X = 3) = 5/36 P(X = 4) = 7/36 P(X = 5) = 9/36 P(X = 6) = 11/36 P = 0 otherwise. Mean(X) = 4.4722 Variance = 1.9715
Yes, Mean is given by, E(X) sum of samples / no. of samples. Variance is Var.(X) = E(X^2) - [E(X)]^2. It is the 1st term which makes the variation of variance independent of mean. In other words, Variance gives a measure of how far the samples are spread out.
Off the top of my head, a perfect F-ratio would be 1.00 which is never possible. All F-ratios will be greater than one so the numerator has to be greater than denominator.
The central limit theorem basically states that for any distribution, the distribution of the sample means approaches a normal distribution as the sample size gets larger and larger. This allows us to use the normal distribution as an approximation to binomial, as long as the number of trials times the probability of success is greater than or equal to 5 and if you use the normal distribution as an approximation, you apply the continuity correction factor.
The types of spatial distribution include: Random distribution: where individuals are arranged without any pattern. Uniform distribution: where individuals are spaced evenly throughout an area. Clumped distribution: where individuals are found in groups or clusters within a larger area.
standard normal is for a lot of data, a t distribution is more appropriate for smaller samples, extrapolating to a larger set.
The distribution is unbalanced, because the right tail is larger than it would be if the distribution were balanced (symmetrical). Also called positive skew. See related link with diagrams that clarify this term.