yes
Y = - 2X - 3 Plot this and see that a line with a negative slope can go through quadrant III.
The slope is a negative number.
depends on line slope
If you mean a slope of -1 then it is: y = -x+5
For a negative slope, the rise is negative and the run is positive.
The slope is always positive A negative slope will always pass through quadrant II and IV
Y = - 2X - 3 Plot this and see that a line with a negative slope can go through quadrant III.
Yes, the slope of a line that passes through quadrant 3 is typically negative. In quadrant 3, both the x and y coordinates are negative, so when you calculate the slope using the formula (change in y / change in x), the result will be negative. This is because as you move from left to right along the line, the y-values decrease as the x-values also decrease, resulting in a negative slope.
The slope is a negative number.
If the slope is negative, y decreases as x increases. The slope goes from top-left of the graph (Quadrant II) to the lower-right of the graph (Quadrant IV).
Yes.. See related link for an example.
depends on line slope
Assuming that one fourth is your way of spelling one fourth, the equation is: y = 0.25x + 3 or 4y = x + 12
-- The definition of 'reverse bias' is anode negative with respect to the cathode, or negative voltage across the diode. That places the graph in negative-x territory. -- The diode simply acts as a resistor. Its unique 'diode' characteristics arise from the fact that its 'resistance' changes with different bias points, but the current through it always has the same polarity as the voltage across it. Therefor . . . -- When the voltage across it is negative, the current through it is also negative. Negative current appears on the graph in negative-y territory. -- Negative-x territory/negative-y territory is the third quadrant.
The slope will be negative.The slope will be negative.The slope will be negative.The slope will be negative.
If you mean a slope of -1 then it is: y = -x+5
For a negative slope, the rise is negative and the run is positive.