No, a square root doesn't have to be a whole number. The square root of 2.25 is 1.5. It could be said that most square roots are not whole numbers. Take just the first few integers (counting numbers). Find the square roots of the numbers 1 through 10 and you'll find three of the numbers have whole number square roots (1, 4 and 9). The other seven don't. For the numbers 11 through 20, there is only 1 number with a whole number square root (16).
The square root of 15 is not a whole number.
The square root of 26 is not a whole number
Negative the square root of 36 is -6, which is a whole number.
nope! take the square root of 5, 2.236067978... which is not a whole number! hope this helps!
When the whole number is a perfect square, ie it is a whole number squared.
The square root of 16 is 4 which is a whole number.
The square root of 15 is not a whole number.
The whole number closest to the square root of 65 is 8. The whole number closest to the square root of 65 is 8.
The square root of 26 is not a whole number
A perfect square root is where the square root of a number equals another whole number. For example, the square root of 144 is 12. 12 is a whole number thus 144 is a perfect square root.
The square root of 55 to the nearest whole number is 7.
Negative the square root of 36 is -6, which is a whole number.
nope! take the square root of 5, 2.236067978... which is not a whole number! hope this helps!
48 is not a square number, so the square root of 48 is irrational and can not be represented as a whole number.
If the whole number is a perfect square, its square root is rational. If not, it's not.
Yes. The square of a whole number is always a whole number. For example, 3 squared is 9, so the square root of 9 is 3. What you never have, is the square root of a whole number being a fraction that is not a whole number. The square root of a whole number is either a whole number or an irrational number. For example, the square root of 2 is irrational, because there are no 2 whole numbers a and b such that a/b squared is 2. This is not terribly difficult to prove, but I have already said too much; I have answered your question.
if its square root is a whole number