We can prove Heron's formula by the equation method. First of all we should know the height of the triangle and the three sides. The working is given below: s=(a+b+c)/2 We must then find: s-a s-b s-c By data, √[s(s-a)(s-b)(s-c)] =1/2bh If the answers are equal, then Heron's Formula has been proved.
Yes, all plane triangle.
For all triangles: area = 1/2 * base * height
No. But all isosceles triangles and equilateral triangles are.
there is no specific formula for isos triangle..... 1/2bh..which means 1/2xbasexheight is the formula for all types of triangles.....so if we take isos as a triangle we can use this formula to calculate the area of the figure!
The title of the formula is "Formula for the Area of a Triangle". No discrimination is expressed or implied.
no only right triangles
No, only right triangles
Heron's Formula is used for finding the area of a triangle given the lengths of its sides. We do not need any angles at all! In geometry, Heron's formula states that the area of the triangle is square root of [s(s-a)(s-b)(s-c)] where is the the semiperimter which is can be found by (a+b+2)/2
All right-angles triangles. That is triangles that contain one angle at 90 degrees.
he worked on the formula of area of a triangle if you have all 3 side lengths
We can prove Heron's formula by the equation method. First of all we should know the height of the triangle and the three sides. The working is given below: s=(a+b+c)/2 We must then find: s-a s-b s-c By data, √[s(s-a)(s-b)(s-c)] =1/2bh If the answers are equal, then Heron's Formula has been proved.
Yes, all plane triangle.
For all triangles: area = 1/2 * base * height
All isosceles triangles are not equilateral triangles
Yes all equilateral triangles are acute triangles, but not all acute triangle are equilateral triangles.
It doesn't matter on the side length, but it MUST have a right angle.