answersLogoWhite

0

No. For instance in R, which is commutative, we have the ideals (2) and (4), where (4) is strictly contained in (2), which is not R. Therefore the ideal (4) is not a maximal ideal.

User Avatar

Wiki User

15y ago

What else can I help you with?

Continue Learning about Math & Arithmetic

Can one formally define a division ring as a field that isn't necessarily commutative?

wedderburn's little theorem says all finite division rings are commutative so they are fields. So if it is a finite division ring, then the answer is NO But for an infinite division ring... I think you can!


How field is denoted in algebra?

A field is a commutative ring in which all non zero elements have inverses or all the elements are units


What are the 11 axioms for ring?

A ring is a mathematical structure defined by the following 11 axioms: Closure under Addition: For any ( a, b ) in the ring, ( a + b ) is also in the ring. Associativity of Addition: For any ( a, b, c ) in the ring, ( (a + b) + c = a + (b + c) ). Commutativity of Addition: For any ( a, b ) in the ring, ( a + b = b + a ). Additive Identity: There exists an element ( 0 ) in the ring such that for any ( a ), ( a + 0 = a ). Additive Inverses: For every ( a ) in the ring, there exists an element ( -a ) such that ( a + (-a) = 0 ). Closure under Multiplication: For any ( a, b ) in the ring, ( a \cdot b ) is also in the ring. Associativity of Multiplication: For any ( a, b, c ) in the ring, ( (a \cdot b) \cdot c = a \cdot (b \cdot c) ). Distributive Property: For any ( a, b, c ) in the ring, ( a \cdot (b + c) = a \cdot b + a \cdot c ) and ( (a + b) \cdot c = a \cdot c + b \cdot c ). Multiplicative Identity (if the ring is unital): There exists an element ( 1 \neq 0 ) such that for any ( a ), ( a \cdot 1 = a ). Commutativity of Multiplication (if the ring is commutative): For any ( a, b ) in the ring, ( a \cdot b = b \cdot a ). No requirement for multiplicative inverses: A ring does not require that every non-zero element has a multiplicative inverse. These axioms define the basic properties of rings in abstract algebra.


Every finite division ring is a field?

correct.


One tree ring equals how much time?

A tree gets a new ring every year, so I suppose a tree ring equals one year.

Related Questions

Problem and solution for maximal ideal in mathematics?

Given a ring R and a proper ideal I of R(that is I ≠ R), I is called a maximal ideal of R if there exists no other proper ideal J of R so that I ⊂ J. Is that the ideal you are talking about? If so, not sure what you want to know?


How do you prove a Ring to be commutative?

To prove a ring is commutative, one must show that for any two elements of the ring their product does not depend on the order in which you multiply them. For example, if p and q are any two elements of your ring then p*q must equal q*p in order for the ring to be commutative. Note that not every ring is commutative, in some rings p*q does not equal q*p for arbitrary q and p (for example, the ring of 2x2 matrices).


In the one-variable polynomial ring R[X], find the condition of a for the ideal (f(X)) generated by the polynomial f(X)≔X^2+aX+a+2 to be the maximal ideal?

Check the attached image


Is Every commutative ring with unity is an integral domain?

Nope. Take the commutative ring Z4 (the set {0,1,2,3} with modular arithmetic and multiplication). 1 is the identity element. But 2 x 2 = 4 = 0 while 2 is not the 0 element. So it's not an integral domain.


Can one formally define a division ring as a field that isn't necessarily commutative?

wedderburn's little theorem says all finite division rings are commutative so they are fields. So if it is a finite division ring, then the answer is NO But for an infinite division ring... I think you can!


What does f.d mean on a ring?

In the context of a ring, "f.d." typically stands for "finitely generated." A finitely generated ring is one that can be generated by a finite set of elements, meaning that every element of the ring can be expressed as a combination of these generators using the ring's operations. This concept is important in algebraic structures, particularly in module theory and commutative algebra.


What does it mean to have a non example of divisor?

A non-example of divisor ring of integers, a division ring or a nonzero commutative ring that has no zero divisors except 0.


What does maximal set of ring mean?

If A intersection E = A where A & E belongs to some some system of sets lets say S then E is called the maximal set of S or the unit set of S.


What has the author David Dobbs written?

David Dobbs has written: 'Advances in Commutative Ring Theory'


What do you know about whole number?

They form a commutative ring in which the primary operator is addition and the secondary operator is multiplication.


How field is denoted in algebra?

A field is a commutative ring in which all non zero elements have inverses or all the elements are units


What does an OH group at position 3 and 4 of the benzene ring of adrenergic drugs result in?

It results in maximal alpha and beta receptor activity.