The displacement, along the direction of measurement, is zero. It need not mean that the object is back at the starting point. The displacement-time graph, measuring the vertical displacement of a ball thrown at an angle, will have displacement = 0 when the ball returns to ground level but, unless you are extremely feeble, the ball will be some distance away, not at its starting point which is where you are. The use of such a graph is not unusual in the elementary projectile motion under gravity.
i dont knoe
baseball being thrown? soccer ball?
A Golf Ball
Their difference is that a 15 gram ball is lighter than a 60 gram ball.
The acceleration of the ball can be estimated by calculating the slope of the velocity versus time graph. If the graph is a straight line, the slope represents the acceleration. The steeper the slope, the greater the acceleration. If the graph is curved, the instantaneous acceleration can be estimated by finding the slope of the tangent line at a specific point on the curve.
look like a ball
If you want the graph to show the acceleration of the ball against time, then the graph is a horizontal line. If you want the graph to show the velocity of the ball against time, then the graph is a straight line sloping downward. If you want the graph to show the height of the ball against time, then the graph is a parabola that opens downward.
The graph will be a straight graph if you plot r2 against v. If we calculate the gradient of the line this is giving us the value of the constant "k" from the equation: k = v r2 With this calculated value of "k" we can calculate the value of the viscosity of the liquid using: Viscosity = 2(Denisity of sphere - Denisty of Glycerol) g 9k
In the traditional scoring system, a dot was used to indicate a ball whereby no run has been scored.
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With a note at the bottom.
The stick to hit the ball in Snooker/Billiards
The displacement, along the direction of measurement, is zero. It need not mean that the object is back at the starting point. The displacement-time graph, measuring the vertical displacement of a ball thrown at an angle, will have displacement = 0 when the ball returns to ground level but, unless you are extremely feeble, the ball will be some distance away, not at its starting point which is where you are. The use of such a graph is not unusual in the elementary projectile motion under gravity.
The force-displacement graph for the strings of a new type of graphite-head tennis racquet is shown in diagram (a). The racquet is tested in a laboratory by being secured vertically and then having a special type of non-deforming tennis ball fired at it horizontally, as shown in diagram (b). The initial velocity of the ball as it strikes the racquet is 10 m s-1 east. After striking the racquet, the ball has a velocity of 9.5 m s-1 west. The mass of the ball is 100 g. What is the maximum displacement of the strings of the racquet during this interaction?
i dont knoe
To calculate the force acting on the ball from the floor, you need to use Newton's second law of motion, which states that force equals mass times acceleration. Acceleration can be calculated as the slope of the velocity-time graph. Given the mass of the ball, you can calculate the force acting on it using this formula.