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It matters which number comes first, as that is the numerator, but all the other numbers (the denominators) can be in any order. x/y/z = x/yz = x/zy = x/z/y

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Q: Does the order of the numbers matter when dividing three different numbers?
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Related questions

Does order matter in division of fractions?

Yes it does. Dividing a by b, is not the same as dividing b by a.


How many different sets of four numbers can you get from six sets of numbers?

6 if order doesn't matter


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If only 1 operation is happening, always go from left to right. it does matter with subtraction.


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It is the same thing as dividing whole numbers in order to find a quotient.


Why is order important when translating subtraction and division expressions?

Order is important because when you switch your numbers when dividing or subtracting, you might get a different answer which would affect your answer. ♫


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No; it does not matter.


How many different ways can 15 be written as the sum of 4 different counting numbers assume the order does not matter?

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Only one, since the order of the numbers does not matter in a combination.


When you divide two numbers does the order of the numbers matter?

yes


How many combinations of 4 numbers are there in 6 numbers?

If the order of the 4 numbers matters, then there are (6 x 5 x 4 x 3) = 360 .If the order of the 4 numbers doesn't matter, then there are 15 different groups of 4.


How many different combinations of four with six numbers if you can't repeat the numbers?

The answer depends on whether order matters. For example, would 1234 be considered the same as 4321. If order does not matter, there are only 15 combinations. This answer was obtained dividing the factorial 6 by the product of the factorial of 4 and the factorial of (6-4). In general, the amount of unordered combinations of x with y numbers is equal to y!/(x!(y-x)!). If order does matter, there are 360 combinations. This answer was obtained by diving the factorial of 6 by the factorial of (6-4). In general, the amount of ordered combinations of x with y numbers is equal to y!/((y-x)!).