There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
9
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
There are 74,974,368 combinations.There are 59C6 = 45,057,474 combinations with 6 different numbers.There are 59C5 = 5,006,386 combinations with 5 different numbers. One of these needs to be duplicated and the one to be duplicated can be chosen in one of 5 ways so there are 25,031,930 of these.There are 59C4 = 455,126 combinations with 4 different numbers. Either one of them appears three times or two are doubled. That can be done in 10 ways so there are 4,551,260 of these.There are 59C3 = 32,509 combinations with 3 different numbers. Either one of them appears 4 times, or one twice and another three times, or all three appear twice. That can be done in 10 ways so there are 325,090 of these.There are 59C2 = 1,711 combinations with 2 different numbers. Either one of them appears 5 times, or one twice and another four times, or both three times. That can be done in 5 ways so there are 8,555 of these.There are 59C1 = 59 combinations with just 1 number, repeated six times so there are 59 of these.Add these together.
The answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
9
59! / 54! = 59 * 58 * 57 * 56 * 55 = 600766320
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
Oh, what a lovely question! To find the number of 5-number combinations from 59 numbers, we can use a formula called combinations. It's like mixing colors on your palette! The formula is nCr = n! / r!(n-r)!, where n is the total numbers (59) and r is the number of selections (5). So, for 59 numbers choosing 5 at a time, there are 5,006,386 unique combinations waiting to be discovered! Just imagine all the beautiful possibilities that can come from those combinations.
There are 74,974,368 combinations.There are 59C6 = 45,057,474 combinations with 6 different numbers.There are 59C5 = 5,006,386 combinations with 5 different numbers. One of these needs to be duplicated and the one to be duplicated can be chosen in one of 5 ways so there are 25,031,930 of these.There are 59C4 = 455,126 combinations with 4 different numbers. Either one of them appears three times or two are doubled. That can be done in 10 ways so there are 4,551,260 of these.There are 59C3 = 32,509 combinations with 3 different numbers. Either one of them appears 4 times, or one twice and another three times, or all three appear twice. That can be done in 10 ways so there are 325,090 of these.There are 59C2 = 1,711 combinations with 2 different numbers. Either one of them appears 5 times, or one twice and another four times, or both three times. That can be done in 5 ways so there are 8,555 of these.There are 59C1 = 59 combinations with just 1 number, repeated six times so there are 59 of these.Add these together.
Any 5 from 59 = 5006386
The answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
-59
The number of combinations is 59C6 which is 59!/[6!*(59-6)!] where n! = 1*2*3*...*n So 59C6 = 59*58*57*56*55*54/(6*5*4*3*2*1) = 45,057,474
It's just a combination of 59 objects chosen five at a time which means (59*58*57*56*55)/(5*4*3*2*1)=5,006,386. Order does not matter in this calculation, which is why it is a combination not a permutation.