7/0 does not exist, but its reciprocal would be 0
The smallest value is 0.
There doesn't exist such a thing. What does exist are standardized variables, which are variables with mean = 0 and standard deviation = 1
There isn't one because that woud be dividing by zero which does not exist.
The limit of cos2(x)/x as x approaches 0 does not exist. As x approaches 0 from the left, the limit is negative infinity. As x approaches 0 from the right, the limit is positive infinity. These two values would have to be equal for a limit to exist.
If the year zero existed the present year would be 2016 AD.
Neither; the year 0 does not exist. The calendar goes from 1 BCE to 1 CE.
0 it does not exist.
LCM of 0 & 50 doesn't exist.
7/0 does not exist, but its reciprocal would be 0
Starting of a new eraAnother Answer:The year '0' does not exist in the Anno Domini (AD - year of our Lord) system that is commonly used in the Gregorian and Julian calendars. It does exist in the astronomical year numbering system and is equivalent to 1 BC in the other two Roman methods.Many biblical scholars would date the birth of Christ to mid-late September to mid-late October in the year 5-4 BC around the time of the Jewish New Year.
A denominator cannot be 0.
0
The least amount would be $0 at a 0.0% rate of interest - which does exist.
the number -0 does not exist so no.
0
The answer to your question does not exist. You have obviously put one to many (0)s in your year. 20009 instead of 2009.