yes
7/0 does not exist, but its reciprocal would be 0
The smallest value is 0.
There doesn't exist such a thing. What does exist are standardized variables, which are variables with mean = 0 and standard deviation = 1
There isn't one because that woud be dividing by zero which does not exist.
The limit of cos2(x)/x as x approaches 0 does not exist. As x approaches 0 from the left, the limit is negative infinity. As x approaches 0 from the right, the limit is positive infinity. These two values would have to be equal for a limit to exist.
If the year zero existed the present year would be 2016 AD.
Neither; the year 0 does not exist. The calendar goes from 1 BCE to 1 CE.
There is no record of who was born on the year 0, mostly because there is a 33 year gap around that period (because it is not known whether the calendar started when Jesus was alive or when Jesus died on the cross, or somewhere in between). Jesus is known to be born on year 0.
Starting of a new eraAnother Answer:The year '0' does not exist in the Anno Domini (AD - year of our Lord) system that is commonly used in the Gregorian and Julian calendars. It does exist in the astronomical year numbering system and is equivalent to 1 BC in the other two Roman methods.Many biblical scholars would date the birth of Christ to mid-late September to mid-late October in the year 5-4 BC around the time of the Jewish New Year.
0 it does not exist.
LCM of 0 & 50 doesn't exist.
7/0 does not exist, but its reciprocal would be 0
The least amount would be $0 at a 0.0% rate of interest - which does exist.
A denominator cannot be 0.
Yes, the concept of "0" exists in this scenario.
0
The answer to your question does not exist. You have obviously put one to many (0)s in your year. 20009 instead of 2009.