since the values of all cards are the same, the winner comes down to the amount of royalty, so 3 queens beats two jacks and 2 fives
3 jacks and two 6s is better then 3 6s and 2 jacks :)
If I am not mistaken it is 3/4.
Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
You have to sound the word out and every beat in the word is a syllable. For example: surrounded = SUR - ROUND - ED The answer for surrounded is three (3) syllables. Answered by Rubystar17 !!! Your Welcome.
since the values of all cards are the same, the winner comes down to the amount of royalty, so 3 queens beats two jacks and 2 fives
Two pair works like this, the higher pair determines who is the winner. Suppose I have two pair Aces and fives, that means I beat all two pair that have kings as the higher pair, and queens etc. So Aces and fives beats Kings and queens. Now, if there is tie then the second pair comes in, so Aces and fives loses to Aces and sevens.
3 jacks and two 6s is better then 3 6s and 2 jacks :)
No, it does not..
The pair of queens beat the pair of tens, the nine and the ace are irrelevant. Queens are higher ranked than tens.
Depends on the value of the Ace and 5, Aces are used as the highest or lowest values in different games. if an ace has any positive value however, 2 aces and 2 fives would beat 1 ace and 2 fives.
No, a full house beats two pair
No. Three of a kind beats two pair in poker hands.
The three sevens beat the three fives. You wouldn't even consider the rank of the pair in this case, since the three-of-a-kind takes precedence. The pairs are important, since they make the hands into full houses (if one king was missing, the five-ace full house would beat the seven trips), but you only compare the best set in this case.
Four of a kind in Poker beats three of a kind. Even four deuces beats three aces.
no
No not in cards