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A rectangle with dimensions 3 cm by 2 cm would meet the criteria. The perimeter is calculated as (2(length + width) = 2(3 + 2) = 10) cm, which does not satisfy the requirement. However, a rectangle with dimensions 4 cm by 1 cm has a perimeter of 10 cm and an area of 4 sq cm. A shape like a triangle with a perimeter of 12 cm and an area of 6 sq cm could be a right triangle with sides of 3 cm, 4 cm, and 5 cm.

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1mo ago

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How to draw a shape with a perimeter that is 12 or 15 or 18 or 21 and the area is 12?

The perimeter and area of a shape do not provide sufficient information. With a given perimeter, the largest area that you can enclose is a circle, but you can then flatten the circle to reduce its area. Similarly, in terms a of quadrilaterals, a square has the largest area, but it can be flexed into a rhombus whose area can be made as small as you like. All that can be said is that there is no shape with a perimeter of 12 units whose area is 12 square units.


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A square....... It has 4 sides so 3 times 4 is 12 - Perimeter..... If each side is 3, 3 times 3 is 9 which is the area.


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No, a shape with a smaller perimeter does not always have a smaller area. The relationship between perimeter and area depends on the specific shape in question. For example, a square with a perimeter of 12 units will have a larger area than a rectangle with the same perimeter. The distribution of perimeter and area varies based on the shape's dimensions and proportions.


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The shape that has an area of 12 and a perimeter of 16 is a rectangle. To find the dimensions of the rectangle, you can set up equations using the formulas for area and perimeter. Let the length of the rectangle be L and the width be W. The equations would be: 2L + 2W = 16 (perimeter) and LW = 12 (area). Solving these equations simultaneously will give you the dimensions of the rectangle.


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