1.6
1/2x=-5
x/2 + 5
3Y - 2 = X + 5 This presumes "a number" and "x" are two separate values. If they are the same number, the equation would be 3X - 2 = X + 5. In this equation, X = 3.5.
.5[12+(t/4)]
-5 + x
(n + 5)/2
5x+17
The appropriate equation is: 5*(-3 + N) = -20
1.6
the quotient of 12 and a number h
1/2x=-5
Half of 18 is 9 and 5+4 = 9 so the number is 5
x/2 + 5
3Y - 2 = X + 5 This presumes "a number" and "x" are two separate values. If they are the same number, the equation would be 3X - 2 = X + 5. In this equation, X = 3.5.
Your equation would be 5(x + 4). In this case it's easiest to work backwards, starting with the "sum of a number and four" part of the problem. This is simply written as x + 4, since we don't know what "a number" is referring to and have to call it x. Then we just need to multiply that answer by 5, so we'd write the equation as 5 * (x + 4) or 5(x + 4). Make sure you have the parentheses, because if not it changes the answer entirely.
.5[12+(t/4)]