Your equation would be 5(x + 4). In this case it's easiest to work backwards, starting with the "sum of a number and four" part of the problem. This is simply written as x + 4, since we don't know what "a number" is referring to and have to call it x. Then we just need to multiply that answer by 5, so we'd write the equation as 5 * (x + 4) or 5(x + 4). Make sure you have the parentheses, because if not it changes the answer entirely.
(3a-8) + 5x(a)
The numbers are 19 and 5
30 is the Answer
5 5+4 = 9 52+42 = 41
The sum of the numbers is 240. If one number is 5 times as big as the other then 240 must be divided by 6. 240/6 = 40. The smaller number must be this while the larger number is 5 times the size. Small number = 40 Larger number = 40 * 5 = 200
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
The sum of number and four times a number is 25 write in algebraic expression
5
That number would be 3
6x + 4 = 5x x = -4
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
8(5+4)+7 = 79
five times the sum of a number and 8 is -15.
5x + 6
20 5 times 4= 20 5+4=9
Answer: 45 4 + 5 = 9 x 5 = 45
54 (5 + 4) x 6 = 54