(v)i = 1000*5+1 = 5001
To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts. Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits. Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits. a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits. b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits. Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.
36 525(365x100=36 5001 extra day every 4 years 100/4=2525+36525)
At least one of the numbers must be negative since 1+3+5+7 = 16, which is too big. Having accepted that, there are infinitely many ways: 1+1+9 + (-1) 1+3+9 + (-3) and so on 1+5001+9 + (-5001) and on and on. Or with 2 negatives: 1+11 -1 -1 1+13 -1 -3 1+15 -1 -5 1+15 -3 -3 etc
the trick to this is to realize the pattern: 10000=0+10000 10000=1+9999 10000=2+9998 ... 10000=4999+5001 so there are 5000 (10000s) and the unmatched 5000 in the middle = 50,005,000
5001 multiply by 10 = 50010
(v)i = 1000*5+1 = 5001
5001 is written as five thousand and one.
because 5001 can be divided by 3 or 1667
5001
5000 I think
5.001 = 5001/5000
5001/1000
5.1 km is the greater distance.5001 m = 5.001 km < 5.1 km
10.002 = 10002/1000 = 5001/500
The Bold and the Beautiful - 1987 1-5001 was released on: USA: 19 February 2007 Belgium: 26 November 2009
5001