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I had that problem to but i went to this http://www.error-repair-tools.com/ppc/index.php?t=5001&gclid=CNyEvf7AvZwCFQZcbQodXkcwoA

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Q: Error -5001 0xffffec75
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How is 5001 written in roman numerals?

(v)i = 1000*5+1 = 5001


What is the total of digits used in numbers from 51 to 5001?

To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts. Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits. Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits. a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits. b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits. Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.


How much days in a century?

36 525(365x100=36 5001 extra day every 4 years 100/4=2525+36525)


How many ways can you add four odd numbers to get the sum of 10?

At least one of the numbers must be negative since 1+3+5+7 = 16, which is too big. Having accepted that, there are infinitely many ways: 1+1+9 + (-1) 1+3+9 + (-3) and so on 1+5001+9 + (-5001) and on and on. Or with 2 negatives: 1+11 -1 -1 1+13 -1 -3 1+15 -1 -5 1+15 -3 -3 etc


What is the total of all of the integers between 1 to 10000?

the trick to this is to realize the pattern: 10000=0+10000 10000=1+9999 10000=2+9998 ... 10000=4999+5001 so there are 5000 (10000s) and the unmatched 5000 in the middle = 50,005,000