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To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts.
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Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits.
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Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits.
a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits.
b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits.
Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.
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What 2 numbers are used in the binary code for computers?
Not 2 numbers - 2 digits. The digits 0 and 1.
How many digits are used for printing a page numbers of a book that has 163 pages?
381 digits.
How many numbers used in PIN at ATM?
It is usually 4 digits. Some banks offer pin numbers that are more than 4 digits long.
How many four digit numbers can be formed from digits 1 2 3 4 if repeated is allowed and how many are odd numbers?
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
'how many digits number system contains'?
There are 10 digits in our number system. The symbols 0,1,2,3,4,5,6,7,8,and 9 are the digits used to create numbers.
What 2 numbers are used in the binary code for computers?
Not 2 numbers - 2 digits. The digits 0 and 1.
How many digits are are used for printing the page numbers of a book that has 115 pages?
Three digits.
How many digits are used for printing a page numbers of a book that has 163 pages?
381 digits.
How many numbers used in PIN at ATM?
It is usually 4 digits. Some banks offer pin numbers that are more than 4 digits long.
How many four digit numbers can be formed from digits 1 2 3 4 if repeated is allowed and how many are odd numbers?
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
'how many digits number system contains'?
There are 10 digits in our number system. The symbols 0,1,2,3,4,5,6,7,8,and 9 are the digits used to create numbers.
What are the digits or numbers used in the octal number system?
Octal (base 8) uses the digits 0 - 7.
What digits are representative of all binary numbers?
There are only two digits used in binary: 0 (zero) and 1 (one).
What numbers are used in binary?
Binary uses only the digits 0 and 1.
What 2 digits are used to represent the bianary system of numbers?
0 and 1
How many 3 digit numbers have at least one repeated digit?
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
When numbering the pages of a book 624 digits were used find the number of pages in the book?
This problem can be solved by applying the counting principle to digits in consecutive page numbers. To begin, we need to separate numbers into their numbers of digits in order to multiply the page numbers to find the number of digits needed to express them. Assuming that your book begins on page 1, there are 9 page numbers having one digit only (counting principle: 9 - 1 + 1 = 9). Since each of these pages is numbered with one digit, the number of digits used is 9 so far. Continue with the pages each numbered with two digits. These are pages 10-99, comprising 90 pages (99 - 10 + 1 = 90). Every page number multiplied by 2 digits each is 180. With the 9 digits coming from single-digit pages, the number of digits used so far is now 189. We can continue in the same manner for pages expressed with three digits, 100-999, but having 435 (624 total - 189 so far = 435) digits left, we probably won't be able to get through all the three-digit numbers. Also, a book is likely to have under a thousand pages. To find out how many pages are left, we divide the number of digits left by the number of digits needed for each page: 435/3 = 145 pages left. Since 145 pages only account for the pages numbered with three digits each, we need to add pages numbered with one and two digits each in order to find the total number of pages. Before 145 pages began to be accounted for, we had accounted for the digits of 99 pages (each numbered using one or two digits each), so the total number of pages is 99 + 145 = 244.
