To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts.
Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits.
Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits.
a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits.
b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits.
Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.
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Not 2 numbers - 2 digits. The digits 0 and 1.
381 digits.
It is usually 4 digits. Some banks offer pin numbers that are more than 4 digits long.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
There are 10 digits in our number system. The symbols 0,1,2,3,4,5,6,7,8,and 9 are the digits used to create numbers.
Not 2 numbers - 2 digits. The digits 0 and 1.
The symbols used in Irish numbers are the same as in English numbers, which are the digits 0-9.
Three digits.
381 digits.
It is usually 4 digits. Some banks offer pin numbers that are more than 4 digits long.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
There are 10 digits in our number system. The symbols 0,1,2,3,4,5,6,7,8,and 9 are the digits used to create numbers.
Octal (base 8) uses the digits 0 - 7.
There are only two digits used in binary: 0 (zero) and 1 (one).
Binary uses only the digits 0 and 1.
0 and 1
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.