56=2x2x2x7
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The numbers that go into 28 evenly are 1, 2, 4, 7, 14, and 28. The numbers that go into 56 evenly are 1, 2, 4, 7, 8, 14, 28, and 56.
As a product of its prime factors: 2*2*2*7 = 56
61 42 56 89
Two of them.
The prime numbers (factors) of 56 are: 2 and 7
The prime numbers (factors) of 56 are: 2 and 7
56=2x2x2x7
Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.
Well, honey, let me break it down for you. The numbers that divide evenly into 56 are 1, 2, 4, 7, 8, 14, 28, and 56. So, if you're looking to divide 56 without any leftovers, those are the lucky numbers you're gonna wanna play with.
there are 9 prime numbers between 56 and 101 these are 59, 61, 67, 71, 73, 79, 83, 89, 97
Well, darling, you're out of luck on this one. Prime numbers are only divisible by 1 and themselves, so there's no way to add three of them together to get 56. You might want to brush up on your math facts before trying to stump me next time.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The numbers that go into 28 evenly are 1, 2, 4, 7, 14, and 28. The numbers that go into 56 evenly are 1, 2, 4, 7, 8, 14, 28, and 56.
56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.
None of those four numbers are prime numbers.