The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
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56=2x2x2x7
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The numbers that go into 28 evenly are 1, 2, 4, 7, 14, and 28. The numbers that go into 56 evenly are 1, 2, 4, 7, 8, 14, 28, and 56.
As a product of its prime factors: 2*2*2*7 = 56
61 42 56 89