The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
56=2x2x2x7
The numbers that go into 28 evenly are 1, 2, 4, 7, 14, and 28. The numbers that go into 56 evenly are 1, 2, 4, 7, 8, 14, 28, and 56.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
As a product of its prime factors: 2*2*2*7 = 56
61 42 56 89
Two of them.
The prime numbers (factors) of 56 are: 2 and 7
The prime numbers (factors) of 56 are: 2 and 7
1, 2, 4, 7, 8, 14, 28, and 56 all divide evenly into 56. These also are all the factors of 56.
56=2x2x2x7
Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.
there are 9 prime numbers between 56 and 101 these are 59, 61, 67, 71, 73, 79, 83, 89, 97
56 does not have only three prime factors.
53 and 3 are two prime numbers that add up to 56
The numbers that go into 28 evenly are 1, 2, 4, 7, 14, and 28. The numbers that go into 56 evenly are 1, 2, 4, 7, 8, 14, 28, and 56.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.