As a product of its prime factors: 2*2*2*7 = 56
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56=2x2x2x7
To find the prime numbers of 56, start with two numbers that when multiplied together equal 56. For example: 2 x 28 = 56. Two is prime, but 28 is composite, so it needs to be factored. 2 x 2 x 14 = 56. Now, 14 is prime, so factor it. 2 x 2 x 2 x 7 = 56. All the factors are now prime, so the prime factors are 2 x 2 x 2 x 7.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
They are: 2+11+43 = 56