Consider the line segment between the points of (6, 8) and (3, 4) Using Pythagoras' theorem its length is: (6-3)squared+(8-4)squared = 25 So the square root of 25 is 5 which is the length of the line
Points: (8, 3) and (8, 7) Slope: 0 The line is a straight vertical line parallel to the y axis
0.12 = 3/25 Dividing by 8 is the same as multiplying by 1/8 => 3/25*1/8 = 3*1/25*8 = 3/200 (=0.015)
3 and 8
6x+3y = 8 3y = -6x+8 y = -3x+8/3 The slope of the line is -3
You need 9 3-to-8 decoders. 8 decoders for selecting one of 64 lines. 1 decoder for enabling 1 decoder out of 8 decoder.
8:256 decoder circuit can be implemented by using 4:16 decoder circuit
Use two 2-4 decoders.
Start with 3/8 decoders and connect only the four outputs of each other that have the first bit 1 loads.
The 74138 is a 3 to 8 decoder. When enabled, one of the 8 outputs is low, based on the binary value of the 3 inputs.
Consider the line segment between the points of (6, 8) and (3, 4) Using Pythagoras' theorem its length is: (6-3)squared+(8-4)squared = 25 So the square root of 25 is 5 which is the length of the line
Decoder is a circuit which have n inputs and 2^n outputs.I think you want to say encoder which have 2^n input and n output lines. So your required chip is 8(2^3)X3 encoder which does not exist.
Points: (8, 3) and (8, 7) Slope: 0 The line is a straight vertical line parallel to the y axis
Please explain specifically your question
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
0.12 = 3/25 Dividing by 8 is the same as multiplying by 1/8 => 3/25*1/8 = 3*1/25*8 = 3/200 (=0.015)
3 and 8