chuma da do chuma da do!
Consider the line segment between the points of (6, 8) and (3, 4) Using Pythagoras' theorem its length is: (6-3)squared+(8-4)squared = 25 So the square root of 25 is 5 which is the length of the line
Points: (8, 3) and (8, 7) Slope: 0 The line is a straight vertical line parallel to the y axis
0.12 = 3/25 Dividing by 8 is the same as multiplying by 1/8 => 3/25*1/8 = 3*1/25*8 = 3/200 (=0.015)
3 and 8
6x+3y = 8 3y = -6x+8 y = -3x+8/3 The slope of the line is -3
You need 9 3-to-8 decoders. 8 decoders for selecting one of 64 lines. 1 decoder for enabling 1 decoder out of 8 decoder.
A full adder can be implemented using a decoder by utilizing a 3-to-8 line decoder to decode the three input bits: A, B, and Carry-in (Cin). The decoder generates eight output lines corresponding to all possible combinations of the three inputs. The outputs of the decoder can then be combined with logic gates to derive the Sum and Carry-out outputs of the full adder. Specifically, the Sum output can be generated by ORing the appropriate outputs of the decoder, and the Carry-out can be derived from a combination of specific outputs as well.
8:256 decoder circuit can be implemented by using 4:16 decoder circuit
Use two 2-4 decoders.
Start with 3/8 decoders and connect only the four outputs of each other that have the first bit 1 loads.
An N-2N decoder is a digital circuit that converts N input lines into 2^N output lines. For each unique combination of the input lines, one specific output line is activated while all others remain inactive. For instance, if there are 3 input lines (N=3), the decoder will produce 2^3 = 8 output lines, allowing it to represent all combinations of the 3 inputs. This type of decoder is commonly used in memory address decoding and data routing applications.
The 74138 is a 3 to 8 decoder. When enabled, one of the 8 outputs is low, based on the binary value of the 3 inputs.
Consider the line segment between the points of (6, 8) and (3, 4) Using Pythagoras' theorem its length is: (6-3)squared+(8-4)squared = 25 So the square root of 25 is 5 which is the length of the line
The 74LS138 is a 3-to-8 line decoder that takes 3 input binary signals and activates one of eight output lines based on those inputs. It features three select inputs (A0, A1, A2) that determine which output (Y0 to Y7) will be low (active), while all other outputs remain high (inactive). The decoder also has enable inputs to control its operation; if the enables are not activated, none of the outputs will be activated. This device is commonly used in memory address decoding and data routing applications.
Points: (8, 3) and (8, 7) Slope: 0 The line is a straight vertical line parallel to the y axis
Decoder is a circuit which have n inputs and 2^n outputs.I think you want to say encoder which have 2^n input and n output lines. So your required chip is 8(2^3)X3 encoder which does not exist.
Please explain specifically your question