3x + 2 = 3x + 6 This is not possible.
The function f(x) = 3x + 2 can take any real value, so the question does not seem to make any sense.
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
It is: 2-3x simplified
x3+3x2+3x+2 divided by x+2 equals x2+x+1
17
y = 3x + 2x^2 + k where k is any number
At x = 3, the value of F(x) = 3x + 2 is the value 11, which graphs to the point (3, 11).
3x + 2 = 3x + 6 This is not possible.
The function f(x) = 3x + 2 can take any real value, so the question does not seem to make any sense.
3x+2.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x-3x+4x^2+8x=4x^2+8x
3x + (-2 + 4x) = -2 + 7x
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
The equivalent expression of 3x-9 plus 3x plus 5 is negative 4.
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?