is 28x squared? if it is, the answer would be, 3(2x+5)(4x+3).
Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2
(5x - 7)(7x + 5)
-12 +/- sq root 104
x2 + 24x +180 = 0 By using the quadratic equation, you can find that x = -12 + 6i or x = -12 - 6i
multiply the base number and add the two exponets together
is 28x squared? if it is, the answer would be, 3(2x+5)(4x+3).
Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2
factor the trinomial 16x^2+24x+9
3x
the GCF is 8x
24x^5 + 24x^3 = 24x^3(x^2 + 1)
(5x - 7)(7x + 5)
The quadratic 4x2+24x+11 = (2x+1)(2x+11)
-12 +/- sq root 104
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
144