factor the trinomial 16x^2+24x+9
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3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4
There is a formula for the "difference of squares." In this case, the answer is (4x + 3)(4x - 3)
4x^(2)(x - 4) + 36(x - 4) (x - 4) is a common factor to both terms, hence (4x^(2) + 36)(x - 4) 4(x^(2) + 9)(x - 4) Done!!!! NB x^(2) + 9 does NOT factor .
18b+9=9(b+2)