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Factor this expression 2 plus 2y plus x plus xy?
2 plus 2y plus x plus x y = 2 plus3y plus 2x (find how many X's there are and add them together and ten Y's and then single numbers)
Factorise xy plus 5yz-2y?
if you take a factor of (Y) you end up with Y(X+5Z-2).
How do you factor 2y squared plus 5y plus 2?
2y^2+5y+2=(2y+1)(y+2)
What is 2 over X plus 1 over Y simplified they are fractions?
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
How do you factor 2y squared minus 9y plus ten?
(2y - 5)(y - 2)
How do you factor xy - 6 plus 2y - 3x?
(x + 2)(y - 3)
Factor this expression 2 plus 2y plus x plus xy?
2 plus 2y plus x plus x y = 2 plus3y plus 2x (find how many X's there are and add them together and ten Y's and then single numbers)
Factorise xy plus 5yz-2y?
if you take a factor of (Y) you end up with Y(X+5Z-2).
What is the answer to xy-x plus 2y-2?
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Factor 4x squared plus 4x plus 2xy plus 2y?
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
How do you factor 2y squared plus 5y plus 2?
2y^2+5y+2=(2y+1)(y+2)
What is 2 over X plus 1 over Y simplified they are fractions?
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
How do you pick out the factors of xy2n2 x2y2n?
To factor the expression ( xy^2n^2 x^2y^2n ), first, identify the common factors in each term. The expression can be rewritten as ( (xy^2n^2)(x^2y^2n) ). The common factors include ( xy^2n ), which appears in both terms. Thus, the factors can be expressed as ( xy^2n (xn^2 + x^2y) ).
What is the common factor of 2x plus 2y?
The common factor is 2.
How do you factor 1 minus x4y4?
(1 - x4y4) = (1 + x2y2)*(1 - x2y2) = (1 + x2y2)*(1 + xy)*(1 - xy)
How do you factor 2y squared minus 9y plus ten?
(2y - 5)(y - 2)
How do you factor 2y plus 14?
2(y + 7)
