2+2y+x+xy=(x+2)(y+1)
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2 plus 2y plus x plus x y = 2 plus3y plus 2x (find how many X's there are and add them together and ten Y's and then single numbers)
if you take a factor of (Y) you end up with Y(X+5Z-2).
2y^2+5y+2=(2y+1)(y+2)
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
(2y - 5)(y - 2)