2+2y+x+xy=(x+2)(y+1)
xy(3x - 2y)(2x + 3y)
if you take a factor of (Y) you end up with Y(X+5Z-2).
(xy - 7)(x^2y^2 + 7xy + 49)
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.
2+2y+x+xy=(x+2)(y+1)
(x + 2)(y - 3)
xy(3x - 2y)(2x + 3y)
if you take a factor of (Y) you end up with Y(X+5Z-2).
(xy - 7)(x^2y^2 + 7xy + 49)
The expression, as given, cannot be factorised.
It is an expression in the form of: xy+7
If that's xy + x^2y, it factors to xy(x + 1) If it's something else, please re-submit your question with any plus signs written out.
xy(x - 2y)(x + 2y)
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.
(y - 3)(x + 2y)
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+