2 plus 2y plus x plus x y = 2 plus3y plus 2x
(find how many X's there are and add them together and ten Y's and then single numbers)
2+2y+x+xy=(x+2)(y+1)
xy(3x - 2y)(2x + 3y)
if you take a factor of (Y) you end up with Y(X+5Z-2).
(xy - 7)(x^2y^2 + 7xy + 49)
The expression (2x + 2y) does not equal (2xy) or (4xy). Instead, it represents the sum of two terms, (2x) and (2y). If you factor it, you could write it as (2(x + y)), but it does not simplify to a product of (xy).
2+2y+x+xy=(x+2)(y+1)
(x + 2)(y - 3)
xy(3x - 2y)(2x + 3y)
To factor the expression ( xy^2n^2 x^2y^2n ), first, identify the common factors in each term. The expression can be rewritten as ( (xy^2n^2)(x^2y^2n) ). The common factors include ( xy^2n ), which appears in both terms. Thus, the factors can be expressed as ( xy^2n (xn^2 + x^2y) ).
if you take a factor of (Y) you end up with Y(X+5Z-2).
(xy - 7)(x^2y^2 + 7xy + 49)
The expression, as given, cannot be factorised.
It is an expression in the form of: xy+7
If that's xy + x^2y, it factors to xy(x + 1) If it's something else, please re-submit your question with any plus signs written out.
xy(x - 2y)(x + 2y)
(y - 3)(x + 2y)
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.