3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)
20x2 - 3x + 10 does not have any real factors.
(x - 6)(x + 9)
(x - 2)(2x + 7)
2(5x - 1)(3x - 2)
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
3x squared minus 25x minus 28
(x + 2)(3x - 1)(3x + 1)
20x2 - 3x + 10 does not have any real factors.
3x^2 -14x +15 = (3x-5)(x-3)
(x - 6)(x + 9)
(x - 2)(2x + 7)
x(3x - 2)
(18x^(2) - 3x) '3x' is a common factor to both terms , so 'take it out'. Hence 3x(6x - 1) Fully factored.
2(5x - 1)(3x - 2)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
(x-3)(3x+1)