For this problem, you may want to use the quadratic formula:
x = (-b +or- sqrt(b2-4ac))/(2a)
where a and b are the coefficients in front of the x2 and x terms, and c is the constant term.
In this case,
a = 1
b = 35
c = 216
Now simply plug these values into the quadratic formula stated above.
x = (-35 +or- sqrt(352-4*1*216)) / (2*1)
x = {-8, -27}
These are the zeros of the function, so we can rewrite the expression given as
(x + 8)(x + 27)
Plug the two calculated values of x into the equation above and you will see that the expression is 0 at both points. To check if this is the correct answer, try expanding and see if it matches the original expression.
25x + 35x + 9 is 60x + 9, which factors to 3(20x + 3)
(5x - 7)(7x + 5)
x2-35x+300 = 0 (x-15)(x-20) = 0 x = 15 or x = 20
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
35x + 115 = 360 35x = 360-115 35x = 245 x = 245/35 x = 7
25x + 35x + 9 is 60x + 9, which factors to 3(20x + 3)
(5x - 7)(7x + 5)
7(5x + 9y)
7(5x + 4y)
x2-35x+300 = 0 (x-15)(x-20) = 0 x = 15 or x = 20
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
35x + 115 = 360 35x = 360-115 35x = 245 x = 245/35 x = 7
42x+35x-35x=42x it's leave 85 so it's change into a negative 42x-85 is the answer
35x + 10
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
x3 + 2x2 - 35x = x(x + 7)(x - 5)