2a2b2+3a2b2-5abc
(x-5)(x+11)
15t+25 = 5(3t+5)
25x + 75 = 25*(x + 3)
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
(a + 6)(a + 4)
15t+25 = 5(3t+5)
(x-5)(x+11)
25x + 75 = 25*(x + 3)
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
(a + 6)(a + 4)
X=5
p2+10d+7
(x+5)(x+3)
4(x2 + 4)
It is: 6(4x+3)
It is 3a(a+3) when factored
x(x+5)