It can't be factored because the discriminant is less than zero.
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
4(x + 2)(x + 2)
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
a2+16 cannot be factored. There are no two numbers whose product is 16 and whose sum is 0.
(4x-3)(x+2)
It can't be factored because the discriminant is less than zero.
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
First you need to solve for y. So write 4x2+y=16 so y=16-4x2 Now write f(x)=16-4x2
16
It is; (2x+4)^2.
4(x + 2)(x + 2)
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
4x2+8x+3 ------> (2x+3)(2x+1)
(y - 8)(y - 2)
a2+16 cannot be factored. There are no two numbers whose product is 16 and whose sum is 0.
1