Rephrase your question, because none of us have any idea what problem 17 is. For now, the area is 42.
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The area of rectangle is : 374.0
Split the cylinder into two circles and a rectangle to find your answer.
Area = 17*8 = 136 square units
187 sq. inches (area for a rectangle= length x width
7 x 17
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
The area of rectangle is : 374.0
Split the cylinder into two circles and a rectangle to find your answer.
Area = 17*8 = 136 square units
187 sq. inches (area for a rectangle= length x width
17 and 22
there is no " weight " on a rectangle. if you mean WIDTH: Keeping in mind that the formula to find an Area of a Rectangle as follow: A= LW ,where A: Area in Square Units, L:Length , W: Width Answer: W=A/L yes their is a "weight" to a rectangle. The formula is W=V(volume)xWD(weight density)
Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.
I am taking this to mean area of 69x17 m rectangle. 1173m2
24*17 = 408 square yards
7 x 17
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 21 feet and the width is 17 feet. Therefore, the area of the floor is 357 square feet (21 feet x 17 feet = 357 square feet).