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Q: How do you find the area of a rectangle with a perimeter of 36m?

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102 m

The formula for finding a rectangle's perimeter is 2(l+w).Here, length is given as 12 m & width as 6m. So, the correct answer is2(l+w)=2(12+6)=2 x 18=36m.

It's 18 36 divided by 2 equals 18

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102 m

The formula for finding a rectangle's perimeter is 2(l+w).Here, length is given as 12 m & width as 6m. So, the correct answer is2(l+w)=2(12+6)=2 x 18=36m.

Assuming you're measuring a rectangle... Okay - you know the length of one side (10m), and the perimeter (36m) The two sides you know total 20m, therefore the sum of the other two sides MUST equal 16m divided by 2 = 8m.

45 percent of -- 36m = 80m45% of x = 36m(45% * x)/45% = 36m/45%x = 36m/45%x = 36m/0.45x = 80m

It is 36m + 72n which can be factorised to 36*(m + 2n)

Each side will be 6. i.e 62 = 36

P=126 L=9+2x w=x 126=2(9+2x)+2x 126= 18+4x+2x 126=18+8x 108=8x 13.5=x So W= 13.5m and L=36m

No. 36M could be interpreted as 36 meters, which is way longer than any bicycle.

The main rectangle of Orion's body occupies a span of Right Ascension from about 5H 15M at Rigel to 5H 55M at Betelgeuse, with the middle star in the belt (Alnilam) almost exactly centered in this range, at RA 5H 36M .

it is 4m

Less than because 3.6m = 360cm but 36m = 3600cm

The GCF is 4.

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