A rectangle 6.3 inches long and 12.2 inches high has an area of 76.86 inches.
Area of a rectangle = length x width = 6.3 x 12.02 = 75.726 sq in
That would be 3 x 9 inches.
Let the length be ( l ) and the height be ( h = 2l ). The perimeter ( P ) of a rectangle is given by the formula ( P = 2(l + h) ). Substituting ( h ) into the perimeter equation, we have ( 210 = 2(l + 2l) = 2(3l) ), which simplifies to ( 210 = 6l ). Solving for ( l ), we find ( l = 35 ) inches, and thus the height ( h = 2l = 70 ) inches.
Length- Height-
To find the area of a rectangle, multiply the length times the width. The result will be in square inches.
Area of a rectangle = length x width = 6.3 x 12.02 = 75.726 sq in
That would be 3 x 9 inches.
Height = Area divided by Length
10 in. A+LS
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
The perimeter of any 2D shape is the sum of all of the individual sides. For example: the perimeter of a rectangle is = length of rectangle (top) + length of rectangle (bottom) + height of rectangle (Left) + height of rectangle (Right)
multiply them
you cant
Length- Height-
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
To find the area of a rectangle, multiply the length times the width.
To find the area of a rectangle, multiply the length times the width. The result will be in square inches.