Given:
x2 + y2 - 6x + 4y = -4
We'll start by rearranging for clarity:
x2 - 6x + y2 + 4y + 4= 0
We can already get a perfect square with our y-value, so let's do that
x2 - 6x + (y + 2)2 = 0
Now to get x down to one term, you need to complete the square:
x2 - 6x + 9 + (y + 2)2 = 9
(x - 3)2 + (y + 2)2 = 32
And that gives you the answer. The circle has a center point of (3, -2), and a radius of 3.
Centre = (0,0), radius = sqrt(5)
Center is (0, 0) . . . the origin.Radius is 7.
The centre is (3,-1) and the radius is sqrt(10).
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
Centre = (0,0), the origin; radius = 11
Centre = (0,0), radius = sqrt(5)
Center is (0, 0) . . . the origin.Radius is 7.
The centre is (3,-1) and the radius is sqrt(10).
That's the equation of a circle with its center at the origin and a radius of 8.
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
Centre = (0,0), the origin; radius = 11
3
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
Draw a circle with its center at the origin and a radius of 3.
It is the equation of a circle with radius of 6 and its center at the origin.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
x2 +y2 = R2 =16 = radius 2 R = 4