x2 + 2x + y2 = 12 (complete the square)
(x2 + 2x + 1)+ y2 = 12 + 1
(x + 1)2 + y2 = 13 (divide by 13 each element to both sides)
(x + 1)2/13 + y2/13 = 1
(x - -1)2/13 + (y - 0)2/13 = 1
Thus, the center of the circle is (-1, 0) and its radius is 1.
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
Centre = (0,0), the origin; radius = 11
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
Radius = 1111
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
Centre = (0,0), the origin; radius = 11
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
Equation of a circle when its centre is at (0, 0): x^2 + y^2 = radius^2 Equation of a circle when its centre is at (a, b): (x-a)^2 + (y-b)^2 = radius^2
Radius = 1111
The centre is (3,-1) and the radius is sqrt(10).
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4
The equation for a circle, centre (a,b), radius r, is:(x-a)+(y-b)=r2So for a circle, centre (-3,2), r=7(x+3)+(y-2)=49
If that equals 16 then the radius is 4