No, it is not a direct variation.
No, direct variation is "y=ax." In direct variation a equals any real constant, b=1, and c must equal zero. If any of thee conditions are changed, it is not direct variation.
Yes
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
Direct variation refers to two variable quantities have a constant (unchanged) ratio, in which a variable "varies directly with the other."In order to have a direct variation, the constant of variation must be not equal to 0 in the equation y=kx, where k is the constant.When you try to put 2x+3y=0 into that formula (y= form), you get:2x+3y=03y=-2x ;Subtract the 2xy=(-2/3)x ;Divide by 3Your constant of variation is -2/3, and since it is less than 0, it is does variate directly. Therefore, y varies directly as x.
No, it is not a direct variation.
No, direct variation is "y=ax." In direct variation a equals any real constant, b=1, and c must equal zero. If any of thee conditions are changed, it is not direct variation.
No.
Oh, dude, direct variation is when two variables change in the same way. In this case, 5x + 3 = 8y + 3, so technically they are changing in the same way by adding 3 to both sides. So, yeah, I guess you could say it's a direct variation, but like, who really cares, right?
Yes
There is only one equation that is given in the question and that equation is not a direct variation.
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
Direct variation refers to two variable quantities have a constant (unchanged) ratio, in which a variable "varies directly with the other."In order to have a direct variation, the constant of variation must be not equal to 0 in the equation y=kx, where k is the constant.When you try to put 2x+3y=0 into that formula (y= form), you get:2x+3y=03y=-2x ;Subtract the 2xy=(-2/3)x ;Divide by 3Your constant of variation is -2/3, and since it is less than 0, it is does variate directly. Therefore, y varies directly as x.
It is -13.
The conditional constant= 1.8*1010
c is any constant value
you have to find the key with the plus and equals symbol. Then push the shift key and the plus/equals key. The "cross" should show up. Plus (+) equals (=). The plus should be above the equals.