To find the midpoint of the segment with endpoints H(8, 13) and K(10, 9), use the midpoint formula: ( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Plugging in the coordinates, we get ( M = \left( \frac{8 + 10}{2}, \frac{13 + 9}{2} \right) = \left( \frac{18}{2}, \frac{22}{2} \right) = (9, 11) ). Therefore, the coordinates of the midpoint are (9, 11).
Midpoint: (-10.5, 5)
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
The midpoint is the point (-10.5, 5) .
End points: (14, 7) and (6, 7) Midpoint: (10, 7)
To find the midpoint of a segment with endpoints (3, 1) and (5, 3), you can use the midpoint formula: ((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})). Plugging in the values, the midpoint is ((\frac{3 + 5}{2}, \frac{1 + 3}{2}) = (4, 2)). Thus, the midpoint of the segment is (4, 2).
(7,4)
The midpoint is at (7, 6)
The midpoint is at: (10, -2)
Midpoint: (8, 7)
If you mean: endpoints of (4, -2) and (5, 1) then its midpoint is at (4.5, -0.5)
Midpoint: (-10.5, 5)
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
The midpoint is the point (-10.5, 5) .
In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposing side.
(6, −4)
(37+73)/2=55
End points: (14, 7) and (6, 7) Midpoint: (10, 7)