Midpoint: (8, 7)
Points: (-1, -9) and (4, -2) Midpoint: (3/2, -11/2)
If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13
4 11 10.8
8
24
The midpoint is at: (10, -2)
-1.5 :]
Points: (-11, 0) and (9, -1) Midpoint: (-1, -1/2)
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
To find the midpoint of the segment with endpoints H(8, 13) and K(10, 9), use the midpoint formula: ( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Plugging in the coordinates, we get ( M = \left( \frac{8 + 10}{2}, \frac{13 + 9}{2} \right) = \left( \frac{18}{2}, \frac{22}{2} \right) = (9, 11) ). Therefore, the coordinates of the midpoint are (9, 11).
(2, -7)
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
B is (-5, 9).
The midpoint of the class interval 7-11 can be calculated by averaging the lower and upper bounds of the interval. To find the midpoint, you add 7 and 11 together and then divide by 2: (7 + 11) / 2 = 18 / 2 = 9. Therefore, the midpoint of the class 7-11 is 9.