(37+73)/2=55
(6, −4)
Endpoints: (1, -6) and (-3, 4) Midpoint: (-1, -1)
Midpoint: (1, 1)
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
The midpoint of a line segment with endpoints at -4, 15 and 22, 3 is (9,9).
(6, −4)
To find the midpoint of a segment with endpoints (3, 1) and (5, 3), you can use the midpoint formula: ((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})). Plugging in the values, the midpoint is ((\frac{3 + 5}{2}, \frac{1 + 3}{2}) = (4, 2)). Thus, the midpoint of the segment is (4, 2).
If you mean endpoints of (-1, 7) and (3, -3) then the midpoint is (1, 2)
Endpoints: (1, -6) and (-3, 4) Midpoint: (-1, -1)
If you mean endpoints of (1, 7) and (3, 3) then the midpoint is at (2, 5).
Endpoints: (1, -6) and (-3, 4) Midpoint: (-1, -1)
Endpoints: (1, -6) and (-3, 4) Midpoint: (-1, -1)
Endpoints: (1, -6) and (-3, 4) Midpoint: (-1, -1)
To find the midpoint of a segment with endpoints (9, -9) and (-3, 7), you can use the midpoint formula: M = ((x₁ + x₂)/2, (y₁ + y₂)/2). Plugging in the coordinates, M = ((9 + (-3))/2, (-9 + 7)/2) = (6/2, -2/2) = (3, -1). Therefore, the midpoint is (3, -1).
Midpoint: (1, 1)
The midpoint is: (-3, 1.5)
The midpoint is: (1.5, -5)