To graph the inequality ( y + 2 > -3(x + 1) ), first, rearrange it to isolate ( y ): ( y > -3x - 3 - 2 ), which simplifies to ( y > -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.
To graph the solution to the inequality (-3x - 720 < 0), you first need to solve for (x). Rearranging the inequality gives (x > -240). On the graph, this means you would draw a number line, shade to the right of (-240), and place an open circle at (-240) to indicate that (-240) is not included in the solution.
It is an inequality in x.
The given expression appears to be incorrectly formatted as an inequality. If you meant to write an inequality such as (-3x + 2y \leq 5y + 9), you can rearrange it to isolate (y). This results in the equivalent inequality (-3x \leq 3y + 9) or (y \geq -x - 3) after simplifying. Please clarify if you meant a different expression.
To graph the equation (3x + 3x + 18), first simplify it to (6x + 18). Next, rewrite it in slope-intercept form (y = mx + b), which gives you (y = 6x + 18). Identify the y-intercept (0, 18) and the slope (6), meaning for every 1 unit increase in (x), (y) increases by 6. Finally, plot the y-intercept on the graph and use the slope to find another point, then draw a line through these points.
3x + y = -1 y = -3x - 1 The graph is a straight line, with a slope of -3, passing through the point Y = -1 on the y-axis.
To graph the solution to the inequality (-3x - 720 < 0), you first need to solve for (x). Rearranging the inequality gives (x > -240). On the graph, this means you would draw a number line, shade to the right of (-240), and place an open circle at (-240) to indicate that (-240) is not included in the solution.
-2
It is an inequality in x.
The given expression appears to be incorrectly formatted as an inequality. If you meant to write an inequality such as (-3x + 2y \leq 5y + 9), you can rearrange it to isolate (y). This results in the equivalent inequality (-3x \leq 3y + 9) or (y \geq -x - 3) after simplifying. Please clarify if you meant a different expression.
This compound inequality cannot be solved.
x < 2/3
To graph the equation (3x + 3x + 18), first simplify it to (6x + 18). Next, rewrite it in slope-intercept form (y = mx + b), which gives you (y = 6x + 18). Identify the y-intercept (0, 18) and the slope (6), meaning for every 1 unit increase in (x), (y) increases by 6. Finally, plot the y-intercept on the graph and use the slope to find another point, then draw a line through these points.
3x + y = -1 y = -3x - 1 The graph is a straight line, with a slope of -3, passing through the point Y = -1 on the y-axis.
6x + 7 < 3x + 106x - 3x
The inequality (6x + 2y - 10 > 0) can be rewritten in slope-intercept form as (y > -3x + 5). The boundary line is (y = -3x + 5), which has a slope of -3 and a y-intercept of 5. The region above this line represents the solution set for the inequality. Since the inequality is strict (>), the boundary line itself is not included in the solution.
First of all, if 'x' is 3, then 'x' doesn't equal -3x+3 . You must mean y = -3x + 3.If x=3, then (-3x + 3) = -6 .The graph is the point (3, -6) .
The answer is x < 0.5