0
Find the midpoint of the segment below and enter its coordinates as an ordered pair?
This can be done with the equation (x1+x2)/2, (y1+y2)/2 which, when solved, creates a (x,x) solution, or a coordinate pair solution. if you had the points (2,4) and (4,8) you would put x1 (2) plus (+) x2 (4) divided by 2, and 2+4 is 6, and 6/2 is 3, so we know our midpoint x value is 3. Then, we would plug in our 'y' values, so we would have y1 (4) + y2 (8) and 4+8 = 12 and 12/2 is 6, so our solution coordinate ordered pair would be (3,6).
What else can I help you with?
What is the midpoint of the segment below (35) (22)?
To find the midpoint of the segment connecting the points (35) and (22), you can use the midpoint formula, which is ((x_1 + x_2)/2) for the x-coordinates. In this case, the midpoint is ((35 + 22)/2 = 57/2 = 28.5). Thus, the midpoint of the segment is at 28.5.
How do you contrust the mid point of a given line?
First, it needs to be a line segment: a line is infinitely long and so has no midpoint.Suppose the line to be bisected is AB. Place the point of a pair of compasses at A with an arc which is greater than half AB. Draw arcs above and below the line segment. Then, move the compass point to B and without changing the arc width, draw fresh arcs to intercept the previous ones at points X and Y. The intersection of the line segment XY and AB is the midpoint of AB.
What is the lenght of the blue segment in L below?
7.74
What is true of the y-coordinates below the x-axis?
They have negative values
How do you get a perpendicular bisector on a line segment?
Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.
What is the x-intercept of the line shown below -2 and 4?
AnFind the midpoint of the segment below and enter its coordinates as an ordered pair. (-3,4) (-3,-2)
What is the midpoint of the segment below (35) (22)?
To find the midpoint of the segment connecting the points (35) and (22), you can use the midpoint formula, which is ((x_1 + x_2)/2) for the x-coordinates. In this case, the midpoint is ((35 + 22)/2 = 57/2 = 28.5). Thus, the midpoint of the segment is at 28.5.
What methods could you use to calculate the x coordinate of the midpoint of a horizontal segment with the endpoints of -6 0 and 6 0?
You could use algebra (see below for how to do that), or you could graph the line and measure it.Using algebraThe x-coordinate of the midpoint of a line segment is the average of the x-coordinates of the end-points. 1/2(-6 + 6) = 0The y-coordinate of the midpoint of a line segment is the average of the y-coordinates of the end-points.1/2(0 + 0) = 0The midpoint of the given horizontal segment is the origin, (0, 0) .
What is the midpoint of the segment below?
There is no segment. You need to click "Add related links" to the left and show an image or something.
What is the midpoint of the segment below (-63) (-65)?
(5/2, - 7/2) Apex
What is the midpoint of the segment shown below apex?
(5/2, - 7/2) Apex
What is the midpoint of the segment shown below (24) an (2-7)?
If you mean points of (2, 4) and (2, -7) then the midpoint is at (2, -1.5)
What is the midpoint of the segment shown below (-4 6) (4-2)?
Points: (-4, 6) and (4, -2) Midpoint: (0, 2)
What is the midpoint of the segment shown below (-24) (6-4)?
If you mean points of (-2, 4) and (6, -4) then the midpoint is at (2, 0)
What is the midpoint of the segment shown below (-12-3) (3-8)?
If you mean (-12, -3) and (3, -8) then its midpoint is at (-4.5, -5.5)
Which of the segment below is a secant?
AD
Do most people function below the wellness midpoint on a health continuum scale?
i knw
