multiply the lenght of the 3 sides... L*W*H=V
2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
B x L x W. base times lenght times height.
d*2*pie/4*l*0.785 Were d is Daimeter of the job, Pie value is 3.142, l is Lenght of the job.
an endpoint is where a segment stops, or ends. (if you found this answer helpful, please click the contributer trust down there l :) l l l v
multiply the lenght of the 3 sides... L*W*H=V
D= Diameter pi= 22/7 L=lenght D x pi x L
2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
B x L x W. base times lenght times height.
d*2*pie/4*l*0.785 Were d is Daimeter of the job, Pie value is 3.142, l is Lenght of the job.
Here is how you do it. If the lenght of the rectangle is L and the Width is W, the perimeter of a rectangle is 2L+2W. To modify this for a square, L=W, so we have 2L+2L where now L is the lenght of a side since all sides have the same length. The formula is 4L. Similarly for the area of a recatangle the formula is LxW, but once again since L=W, we have L2.
an endpoint is where a segment stops, or ends. (if you found this answer helpful, please click the contributer trust down there l :) l l l v
The perimeter of a rectangle is 2L + 2W. L will be used for lenght. Since the width is 6 inches less than the lenght, width can be defined as L-6. So you use substution. 2(L) + 2(L-6) = 52 2L + 2L -12 = 52 4L = 64 L = 16 Since L = 16 and the width is L-6 --->16-6 = 10 for your width.
It depends on two variables v : speed of sound within this object L : main lenght of this object The natural frequency of the object will be v/L
No Time period, T = 2π √(l/g) π - pi l - lenght of the pendulum g - acceleration due to gravity at the place
L x W x H Lenght x Width x Hieght
P*H+2*(L*B) Perimeter*Height+2*(lenght*Breadth)