To do this manually, you can simply read through the number, keeping a manual tally in your head.
If you are looking for an algorithm to do it for you, here is one method that would work in C, where "number" is the value being tested and "digit" is the digit we're counting:
...
int whole = (int)number;
number -= whole;
tally = 0;
while(whole != 0){
if(whole % 10 digit) tally++;
number -= (int)number;
}
printf("We counted %i digits occurrences of the digit %i\n", tally, digit);
...
Chat with our AI personalities
find the diagonal method of two digit number and three digit number
To find how many sevens there are from 1 to 1000, we can consider the occurrences of the digit '7' in each digit place (hundreds, tens, and units). In the range from 1 to 999, the digit '7' appears 300 times: 100 times in each of the hundreds, tens, and units places. Including the number 1000, which has no sevens, the total remains 300. Thus, there are 300 occurrences of the digit '7' from 1 to 1000.
To find how many times the digit 2 occurs in the tens place from 100 to 1000, we can analyze the range of numbers. The relevant range for the tens place is from 120 to 229, which includes all numbers where the tens digit is 2. This gives us the numbers 120-129 (10 occurrences), 220-229 (10 occurrences), totaling 20 occurrences of the digit 2 in the tens place.
It is 63.
first you look at the first number tell what that number is then you just find the first digit.