The number of permutations of the letter SUM is 3 factorial, or 6. Since none of those letters are repeated, the issue of repetition is not a factor. Perhaps the questioner meant to use a different word. If so, please restate the question.
It is 720.
The letters A B O U T can be arranged 120 different ways. This is the number of permutations of 5 things taken 5 at a time, or 5 factorial.
Assume that the question is really looking for an "odd" number, (not an "old" number).Then it's [ 1001 ].
The word "party" consists of 5 unique letters. The number of ways to arrange these letters is calculated using the factorial of the number of letters, which is 5!. Therefore, the total number of arrangements is 5! = 120.
It is 10000.
It is 720.
Since in the word "party" no letters are repeated, the letters can be arranged in 5! ways, or 120.
The Modern Periodic Law states that there will be a periodic repetition of properties when the elements are arranged according to increasing atomic number.
Modern Periodic Law.
The number of different ways the letters of a word can be arranged, when all the letters are different, is the same as the number of permutations of those letters. In this case, the answer is 5!, or 120.
This statement is a fundamental principle of the periodic law, proposed by Dmitri Mendeleev. The periodic law states that when elements are arranged by increasing atomic number, there will be a periodic repetition of their properties.
This is called periodicity.
number
Mendeleev's table was also based upon his Periodic Law, which stated that when elements are arranged by increasing atomic number, there is a periodic repetition of similar chemical and physical properties.
The letters A B O U T can be arranged 120 different ways. This is the number of permutations of 5 things taken 5 at a time, or 5 factorial.
erties, known as the periodic law. This arrangement is known as the periodic table, where elements with similar properties are placed in the same column. The periodic table helps to predict an element's properties based on its position.
Assume that the question is really looking for an "odd" number, (not an "old" number).Then it's [ 1001 ].