You have to find out all combinations of dice that give you 7: that would be 1-1-5; 1-2-4; 1-3-3; 1-4-2; 1-5-1; 2-1-4; 2-2-3; 2-3-2; 2-4-1; 3-1-3; 3-2-2; 3-3-1; 4-1-2; 4-2-1; 5-1-1. I hope I didn't miss any, that would be 15 favorable combinations; the total of possibilities with 3 dice is 63 = 216, so the probability is 15/216 = 5/72, or about 6.9%.
1:6
50%. There are three dice; each die has 6 faces.
The probability is 1/36.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
Three out of six which reduces to one half.
The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
With one roll of three dice, the probability is 7/8.
5/216
The probability is 5/16 = 0.3125
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
There are 36 permutations of rolling two dice. Three of them, (4,6), (5,5), and (6,4) add up to ten. Therefore, the probability of rolling ten on two dice is 3 in 36, or 1 in 12, or about 0.0833.
1:6
The probability of rolling doubles with two dice is 1 in 6, or about 0.167.
50%. There are three dice; each die has 6 faces.
The probability is 1/36.
0% probability
It is 1/36.