The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
If you roll the die often enough, the probability of getting a 2 ones in a row is 1. In only 2 rolls, the answer is (1/6)*(1/6) = 1/36
Its not an exact thing like with circle radius, but basically add together all the numbers and make a fraction like if there are 3 yellow balls, 3 green ones and 5 blue ones in a bag, then you add 3+3+5 = 11, and then you figure out that the probability of picking a blue ball out of the bag is 5/11. Probability is the ratio of all outcomes that you define as being of interest divided by all possible outcomes. For example, the number of ways to get doubles on 2 6-sided dice is 6 (1,1 2,2, 3,3 4,4 5,5 6,6) but there are 36 different ways for the dice to turn up so the probability of getting doubles on a single roll is 6/36 = 1/6 Likewise there are 6 ways to roll a 7 (1,6 2,5 3,4 4,3 5,2 6,1) so the odds of rolling a seven on a single roll are 6/36 = 1/6 The math gets more involved as you start looking at situations where the odds of getting any one of the particular outcomes are not the same - for example, with loaded dice - or where you are looking at a sequence of events.
Calculating getting a five on a dice:There are 6 sides to a dice so there would be 12 in a pair of dice. So you would have a 1 in 6 chance of rolling a 5.Calculating getting a sum of five:There are a total of 18 combinations you can get when rolling two dices. 1+1, 1+3, 1+4, 1+5, 1+6, 2+2, 2+3, 2+4, 2+5, 2+6, 3+3, 3+5, 3+6, 4+4, 4+5, 5+5, 6+4, and 6+6 (I eliminated ones which were equal to others such as eliminating 6+2 because it is the same as 2+6). Out of the combination of numbers, only two are able to sum up to five (2+3 and 1+4). This equals about an 11.1% chance of rolling two which equal 5 when added together.
(assuming that the probability of having a girl or a boy is 50/50) Looking from beforehand, the probability of having three boys then a girl is the probability of each of these events happening multiplied together. That is 50% x 50% x 50% x 50% or 0.54 This would mean that the chance of having a girl after three boys is 0.0625. If you've already had the three boys though, it is a different story. The point is that previous experiences do not affect future ones; probability has no memory. Thus the probability of having a girl next is 50%, regardless of if you've had boys or girls in the past. To think otherwise is known as the gambler's fallacy, where a gambler says "black has come up 4 times in a row, it must be red next" even though the chance of red is always 50%
There are 16 marbles total and 7 green ones, so the probability is 7/16.
The probability of rolling 3 ones with 4 dice is:4C3 (1/6)3 (5/6) = 0.015432098... ≈ 1.54%
The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%
If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.
1/361/6 x 1/6 = 1/36
(1/6)^3 since each event is independent and each has a probability of 1/6.
1/6+1/6+1/6-1/6 =.333
(5/6)^100, or approximately 0.0000012%
The odds of rolling 5 ones is 1/6 *1/6 *1/6 *1/6 *1/6 = 1/7776
( 2 / 36 ) x ( 2 / 36 ) = 0.003086 (rounded)
Shut the Box is a dice game where players try to flip down all the numbers on a board by rolling dice and adding up the numbers to match the ones still standing. The rules vary, but generally, players take turns rolling the dice and flipping down numbers that add up to the dice total. Strategies include deciding which numbers to flip down first and managing risk by considering the probability of rolling certain numbers. The player with the lowest score when all numbers are flipped down wins.
The probability that there will be EXACTLY one five when four dice are rolled is 500/1296 = 125/324, or about 38.58%. The odds are 199 to 125 against, or about 8 to 5. The probability that there will be AT LEAST one five when four dice are rolled is 671/1296, or about 51.77%. The odds are 625 to 671 against, or about 14 to 15.
The odds of rolling a single one on a 20-sided die is 1 in 20 (1/20). Since the rolls are independent events, the odds of rolling two ones on two 20-sided dice would be (1/20) * (1/20), which simplifies to 1 in 400 (1/400).