Let (x1, y1) = (-3, -4) and (x2, y2) = (3, -2). Thus, the slope is 1/3.
m = (y2 - y1)/(x2 - x1) = (-2 - -4)/(3 - -3) = (-2 + 4)/(3 + 3) = 2/6 = 1/3.
find the slop of the line passing through (1,5) and (0,2)
Another set of points are needed to find the slope.
9,12
17
This question mathematically makes no sense. A line passing through any given point can have any slope at all; you need two points to uniquely determine a line (and therefore the slope of that line).
Find the slope of the line passing through (5, 5) and (-4, 5).
find the slop of the line passing through (1,5) and (0,2)
Since the line is horizontal, the slope is zero.
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
Another set of points are needed to find the slope.
9,12
4/1
it's 4/7 And you need to write the questions like this: "Find the slope of the line pasing through (3,4) and (10,8)"
17
This question mathematically makes no sense. A line passing through any given point can have any slope at all; you need two points to uniquely determine a line (and therefore the slope of that line).
-1/4
84