(10x - 8)(2x - 1) = 0
x = 4/5 or 1/2. It's easier to check in decimal: 0.8 or 0.5
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
The equation ( x - 3 = 0 ) can be solved by isolating ( x ). By adding 3 to both sides of the equation, we find that ( x = 3 ). Thus, the solution to the equation is ( x = 3 ).
The solution
To find the solution of the system of equations ( y = -2 + 5 ) and ( y = x - 5 ), we first simplify the first equation to ( y = 3 ). Next, we set ( 3 = x - 5 ) from the second equation and solve for ( x ), yielding ( x = 8 ). Therefore, the solution to the system is the point ( (8, 3) ).
The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
Nobody can help you find a solution until you get another equation to go along with this one. Your equation has two variables in it ... 'x' and 'y' ... so it has no unique solution all by itself.
(Since 5 times 20 does equal 100, the solution is correct.
The equation ( x - 3 = 0 ) can be solved by isolating ( x ). By adding 3 to both sides of the equation, we find that ( x = 3 ). Thus, the solution to the equation is ( x = 3 ).
The solution
To find the solution of the system of equations ( y = -2 + 5 ) and ( y = x - 5 ), we first simplify the first equation to ( y = 3 ). Next, we set ( 3 = x - 5 ) from the second equation and solve for ( x ), yielding ( x = 8 ). Therefore, the solution to the system is the point ( (8, 3) ).
The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)
The second equation is not complete and there is not sufficient information for a solution. It would make no sense for me to guess what a + b equals since, in that case, I may as well start posting my own questions and answering them!
This is an equation of a straight line. A solution for two unknowns requires two (independent) equations; there is only one here. Every point that is on that line is a solution to the equation. So you can let x be any real number and find a corresponding y. This ordered pair (x,y) will be a solution to the equation as well as a point on the graph of the line.
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
A two-step equation with a variable that equals 23 could be (2x + 5 = 23). To solve for (x), first subtract 5 from both sides to get (2x = 18), and then divide by 2 to find (x = 9). Thus, the solution satisfies the original equation.